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4x^2+24x-85=0
a = 4; b = 24; c = -85;
Δ = b2-4ac
Δ = 242-4·4·(-85)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-44}{2*4}=\frac{-68}{8} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+44}{2*4}=\frac{20}{8} =2+1/2 $
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